Question

A 960 kg car initially moving at 30.0 m/s hits a 150-kg deer initially running at 12.0 m/s in the same direction. After the hitting. the deer remains on the car. What is the final velocity (in m/s)?

Answer 1

V = 27.56 m/s

Step-by-step explanation:

It is given that,

Mass of the car,
`m_1=960\ kg`

Initial speed of the car,
`u_1=30\ m/s`

Mass of the deer,
`m_2=150\ kg`

Initial speed of the deer,
`u_2=12\ m/s`

It is mentioned that after the hitting. the deer remains on the car. It is a case of inelastic collision. Let V is the speed of final speed of the deer and the car. Using the conservation of momentum to find it as :

`m_1u_1+m_2u_2=(m_1+m_2)V`

`V=(m_1u_1+m_2u_2)/((m_1+m_2))`

`V=(960* 30+150* 12)/((960+150))`

V = 27.56 m/s

So, the final velocity of the deer and the car is 27.56 m/s.