Question

An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 300 N. (a) What is the equivalent spring constant of the bow?N/m(b) How much work is done in pulling the bow?

Answer 1

a) 750 N/m

b) 60 J

Step-by-step explanation:

the elongation of the bowstring x = 0.4 m

force F on full elongation= 300 N

now we know that F=kx

⇒k= F/x

`k= (300)/(0.4) = 750 N/m`

work done in pulling

W=
`(1)/(2)kx^2`

W=
`(1)/(2)750*0.4^2`

W=60 J