A golfer angles a shot at 18.0° to the horizontal with an initial velocity of 62.0 m/s. How far does the ball travel before striking the ground? Ignore air resistance.

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asked May 25, 2020 137k views

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A golfer angles a shot at 18.0° to the horizontal with an initial velocity of 62.0 m/s. How far does the ball travel before striking the ground? Ignore air resistance.

Physics
college

Vincent Zoonekynd asked

by Vincent Zoonekynd

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Answer:

372.67m

Step-by-step explanation:

R=Ux cos 18 × t

= 62 cos 18 x (63÷9.81)

=372.67m

because t = u/g

g= 9.81

Bilel Chaouadi answered May 29, 2020

by Bilel Chaouadi

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