Final answer:
The total distance traveled by the red spot as one cycle of the transverse wave passes by is 4A.
Step-by-step explanation:
The total distance traveled by the red spot as one cycle of the transverse wave passes by is 4A.
To understand why, it helps to think about how the wave moves. In a transverse wave, the particles of the medium oscillate perpendicular to the direction of wave propagation. This means that as the wave moves forward, each individual particle moves up and down.
During one complete cycle of the wave, the red spot on the string will go through one complete oscillation, which consists of both an upward displacement and a downward displacement. So, it will travel a distance equal to twice the amplitude, which is 2A, both upwards and downwards in total. Therefore, the total distance traveled by the red spot is 2A + 2A = 4A.