Question

The average rate of disappearance of ozone in the reaction is found to be 8.76× 10¯3atm over a certain interval of time. What is the rate of appearance of during this interval?

Answer 1

13.14×10^{-3} atm

Step-by-step explanation:

`2O_3(g)\rightarrow3O_2(g)`

therefore, rate is given as

=
`-(1)/(2)(dO_3)/(dt) = +(1)/(3) (dO_2)/(dt)`

=
`(dO_2)/(dt) = +(3)/(2) \frac{dO_3}=(3)/(2)*8.76*10^(-3){dt}`

= 13.14×10^{-3} atm