Question

A 0.59-kg block is hung from and stretches a spring that is attached to the ceiling. A second block is attached to the first one, and the amount that the spring stretches from its unstretched length triples. What is the mass of the second block?

Answer 1

Answer: 1.77kg

Step-by-step explanation:

Using the concept or hooke's law, the force (F) applied to a string is directly proportional its extension (e)

F=ke

K is the elastic constant

If the mass applied initially is 0.59kg i.e 5.9N force, we have

5.9=ke... (1)

If a second block is attached let's say 'm', its force will be 10m, and the extension will become 3e

10m = 3ke ... (2)

Dividing eqn 1 by 2,

5.9/10m = ke/3ke

5.9/10m = 1/3

10m = 5.9×3

m = 5.9×3/10

m = 1.77kg