Question

A large water tank is 3.10 m high and filled to the brim, the top of the tank open to the air. A small pipe with a faucet is attached to the side of the tank, 0.480 m above the ground. If the valve is opened, at what speed (in m/s) will water come out of the pipe?

Answer 1

7.2 m/s

Step-by-step explanation:

H = 3.10 m

h = 0.480 m

v = ?

density of water, d = 1000 kg/m^3

Pressure, = Po = atmospheric pressure

Use Bernoulli's theorem

Po + dgH + 1/2 x d u² = Po + d g h + 1/2 d v²

here, u = 0

g H = g h + v²/2

2 x 9.8 x (3.10 - 0.480) = v²

v = 7.2 m/s

thus, the speed of water is 7.2 m/s.

Answer 2

7.16 m /s

Step-by-step explanation:

The depth of the small pipe attached with the side wall of tank from the surface of water

h =( 3.1 - .48 )m

= 2.62 m

velocity of flow of water

= √ 2 g h

= √ 2 x 9.8 x 2.62

= 7.16 m /s