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Light of wavelength 480 nm illuminates a pair of slits separated by 0.27 mm. If a screen is place 1.7 m from the slits, determine the distance between the first and third dark fringes.

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4 votes

Answer:

Δy = 6.05 mm

Step-by-step explanation:

The double slit phenomenon is described by the expression

d sin θ = m λ constructive interference

d sin θ = (m + ½) λ destructive interference

m = 0,±1, ±2, ...

As they tell us that they measure the dark stripes, we are in a case of destructive interference, let's use trigonometry to find the sins tea

tan θ = y / x

y = x tan θ

In the interference experiments the measured angle is very small so we can approximate the tangent

tan θ = sin θ / cos θ

cos θ = 1

tan θ = sin θ

y = x sin θ

We substitute in the destructive interference equation

d (y / x) = (m + ½) λ

y = (m + ½) λ x / d

The first dark strip occurs for m = 0 and the third dark strip for m = 2. Let's find the distance for these and subtract it

m = 0

y₀ = (0+ ½) 480 10⁻⁹ 1.7 / 0.27 10⁻³

y₀ = 1.511 10⁻³ m

m = 2

y₂ = (2 + ½) 480 10⁻⁹ 1.7 / 0.27 10⁻³

y₂ = 7.556 10⁻³ m

The separation between these strips is Δy

Δy = y₂-y₀

Δy = (7.556 - 1.511) 10⁻³

Δy = 6.045 10⁻³ m

Δy = 6.05 mm

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