Question

A vertical scale on a spring balance reads from 0 to 160 N . The scale has a length of 11.5 cm from the 0 to 160 N reading. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.95 Hz .

Answer 1

Mass of Fish=4.052 kg

Step-by-step explanation:

I think you want to find mass of fish hanging

So

Given Data

F (Force)=160 N

l (length)=11.5 cm

f (frequency)=2.95 Hz

m (Mass of Fish)=?

Solution

first we have find Spring Constant

`k=(160)/(11.5)*100\\ k=1391 (N)/(m)`

The Motion described by

`Angular frequency=\sqrt{(Spring Constant)/(mass) }\\ w=\sqrt{(k)/(m) }\\  w^(2)=(k)/(m)\\  m=(k)/(w^(2) )\\  m=(1391)/((2*(3.14)*f)^(2) )\\ m=(1391)/((2*(3.14)*2.95)^(2) )\\ m=4.052kg`