Question

A biased coin has a 0.6 chance of coming up heads when flipped. Find the probability of flipping 3 or fewer heads in 10 flips. What is the expected number of heads in 10 flips

Answer 1

0.04247,6

Explanation:

Given that a biased coin has a 0.6 chance of coming up heads when flipped

X no of coins which showed head is binomial with p = 0.6 since each trial is independent of the other

When there are 10 flips we have n =10

This gives

probability of flipping 3 or fewer heads in 10 flips.

=
`P(X=3)\\=10C3 (0.6)^3 (0.4)^7\\= 0.04247`

Expected number of heads in 10 flips

E(x)

=
`np = 6`