Question

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s ). If a particular disk is spun at 352.9 rad/s while it is being read, and then is allowed to come to rest over 0.167 seconds , what is the magnitude of the average angular acceleration of the disk?

Answer 1

Angular Acceleration=2113.17
`(rad)/(sec^(2) )`

Step-by-step explanation:

Given Data

w (angular speed)=352.9 rad/sec

t (time)=0.167 sec

a (angular acceleration)=
`(w)/(t) \\a=(352.9)/(0.167) \\a=2113.17(rad)/(sec^(2) )`