Question

Calculate the total number of bits required for the cache listed above, assuming a 32-bit address. Given that total size, fi nd the total size of the closest direct-mapped cache with 16-word blocks of equal size or greater. Explain why the second cache, despite its larger data size, might provide slower performance than the fi rst cache.

Answer 1

To calculate the total number of bits required for the cache, you need the cache size and block size. The second cache, despite its larger data size, might provide slower performance than the first cache.

Step-by-step explanation:

To calculate the total number of bits required for the cache, we need to know the cache size and block size. Without that information, it is not possible to answer the question accurately.

However, assuming we have the necessary information, the total number of bits required for the cache can be calculated using the formula:

Total bits = Block size (in bytes) * Number of blocks in the cache * Number of bits in the address

As for the second part of the question, where we need to find the closest direct-mapped cache with 16-word blocks of equal size or greater, we would need to know the cache size of the first cache in order to compare.

The second cache, despite its larger data size, might provide slower performance than the first cache due to factors such as cache access time, cache hit rate, and cache coherence.

Answer 2

Number of bits in a cache = 2588672 bits

Cache with 16- word block of equal size or greater =4308992

Step-by-step explanation:

To calculate the number of bits required for the cache containing 32- bit address.

formula to calculate the bits is :

Number of bits in a cache
`(2^index bits) * (valid bits + tag bits + (data bits * 2^offset bits))`

total bits =
`2^15 (1+14+(32*2^1))` = 2588672 bits

Cache with 16- word block of equal size or greater

total bits =
`2^13(1 +13+(32*2^4))` =4308992