Question

Struggling with this section. If someone could help me on this one and 4 more questions like this that would be very helpful!

Answer 1

`$ (1)/(45) $`

Explanation:

There are 10 balls. They are placed in a bag. So, the number of sample space, n(S) = 10.

Now, the probability of drawing the first yellow ball =
`$ \frac{No. \hspace{2mm} of \hspace{2mm} yellow \hspace{2mm} balls}{Total \hspace{2mm} No. \hspace{2mm} of \hspace{2mm} balls} $`.

Probability of drawing first ball =
`$ (2)/(10) $`

Now, another yellow ball is to be drawn without replacing the first ball drawn.

Therefore, the number f total balls now becomes 9 and the number of yellow balls become 1.

Hence, the probability becomes
`$ (1)/(9) $`

The total probability becomes
`$ (2)/(10) * (1)/(9) $` =
`$ (1)/(45) $`.