Answer:
Fe(s) ⇒ Fe²⁺ + 2e⁻ Oxidation
Step-by-step explanation:
Oxidation is the loss of electrons, so what we have to do here is to determine the change in oxidation of the atoms in the reaction and identify the species which loses electrons.
Sn⁴⁺ + 2e⁻ ⇒ Sn²⁺ Reduction
Fe(s) ⇒ Fe²⁺ + 2e⁻ Oxidation
Then the oxidation half-reaction is:
Fe(s) ⇒ Fe²⁺ + 2e⁻ Oxidation