Question

A solution is made by mixing 100.g of acetic acid HCH3CO2 and 48.g of acetone CH32CO. Calculate the mole fraction of acetic acid in this solution. Round your answer to 3 significant digits.

Answer 1

`x_(A.A)=0.668`

Step-by-step explanation:

Hello!

In this case, since the mole fraction involves the moles of each substance, we first compute them considering the molar masses of acetic acid and acetone to be 60.052 and 58.08 g/mol respectively:

`n_(A.A)=(100gA.A)/(60.052g/mol)=1.67molA.A\\n_(acetone)=(48gAcetone)/(58.08g/mol) =0.824molAcetone`

Thus, the mole fraction of acetic acid is computed below:

`x_(A.A)=(n_(A.A))/(n_(A.A)+n_(Acetone)) =(1.67mol)/(1.67mol+0.826mol)\\\\ x_(A.A)=0.668`

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