Question

Suppose a clay model of a koala bear has a mass of 0.205 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay model, which is initially motionless and has a mass of 0.320 kg. Both being soft clay, they naturally stick together. What is their final velocity (in m/s)? (Enter the magnitude.)

Answer 1

Final velocity, v = 0.28 m/s

Step-by-step explanation:

Given that,

Mass of the model,
`m_1=0.205\ kg`

Speed of the model,
`u_1=0.72\ m/s`

Mass of another model,
`m_2=0.32\ kg`

Initial speed of another model,
`u_2=0`

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

`m_1u_1+m_2u_2=(m_1+m_2)V`

`V=(m_1u_1+m_2u_2)/((m_1+m_2))`

`V=(0.205* 0.72+0.32* 0)/((0.205+0.32))`

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.