Question

You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.220 kg. All of the ice melts, and the final equilibrium temperature of the two substances is 0.00∘C. What was the initial temperature of the copper cube? Assume no heat is exchanged with the surroundings.

Answer 1

`T = 29.66 ^o C`

Step-by-step explanation:

As we know that here final equilibrium temperature is 0 degree C

so we can use energy conservation here

heat given by the cube = heat absorbed by the ice

so we have

`ms \Delta T = m' L`

so here we have

`0.220(385)(T - 0) = (7.50 * 10^(-3))(3.35 * 10^5)`

`T = (2512.5)/(0.220 * 385)`

`T = 29.66 ^o C`