Answer:

Explanation:
Recall that the function cos(x) shows an oscillating curve between the values -1 and 1 on the vertical axis (the Range of this goes therefore between y = -1 to y=1).
Now, when you multiply this trig function by "-3", its amplitude increases, and therefore it will be now oscillating between the values y=-3 and y=3.
if to this, you now add 1 (to complete the function: f(x) = -3 cos(x) +1, you are translating the full function one unit up. Then the new function will be still oscillating, but between the values y=-2 and y = 4 (the previous ones shifted up by 1 unit)
Therefore, the answer to the question is:
Range of f(x) is {
}, which coincides with your last answer choice.