Answer:
There is no statistical evidence to prove that mean is atleast 60
Explanation:
Given that a department store manager believes that the average age of their customers is at least 60.

(Right tailed test)
significance level = 1%
Data given is
70 48 41 68 69 55 70 57 60 83
32 60 72 58 88 48 59 60 56 65
66 60 68 42 57 59 49 70 75 63
44
Mean 60.93333333
std dev 12.00268169
Std error 2.155745271
df = 30
Mean difference = 0.93
Test statistic = mean difference/std error
= 0.431405
p value = 0.3346
Since p >0.01 we accept null hypothesis
There is no statistical evidence to prove that mean is atleast 60