Question

A body oscillates with simple harmonic motion along the x axis. Its displacement varies with time according to the equation x = 5 sin (πt + π/3). What is the phase of the motion (in rad) at t = 2 s?

Answer 1

θ = (7π / 3) rad

Step-by-step explanation:

given,

displacement of simple harmonic motion along x-axis

equation is given as

x = 5 sin (π t + π/3 )

general equation of simple harmonic motion

x = A sin θ

θ is the phase angle

θ = π t + π/3

at t = 2 s

`\theta =\pi * 2 +(\pi)/(3)`

`\theta =(7\pi)/(3)\ rad`

Phase of the motion at t =2 s is θ = (7π / 3) rad