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Use the method of half-reaction to complete and balance the following redox reaction, and determine how many moles of electrons are transferred according to the balanced reaction.ClO−4 NO2(g)⟶Cl2(g) NO−3(aq)

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Answer:

Total 14 electrons are transferred.

Step-by-step explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.


X\rightarrow X^(n+)+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.


X^(n+)+ne^-\rightarrow X

For the given chemical reaction:


ClO_4^-(aq)+NO_2(g)\rightarrow Cl_2(g)+NO_3^-(aq)

The half cell reactions for the above reaction follows:

Oxidation half reaction:
NO_2+H_2O\rightarrow NO_(3)+e^-+2H^+

Reduction half reaction:
2ClO_4^(-)+14e^-+16H^+\rightarrow Cl_2+8H_2O

As,
NO_2 is loosing 1 electron and
ClO_4^(-) is gaining 14 electrons. Thus,

Balancing this:-

Oxidation half reaction:
14NO_2+14H_2O\rightarrow 14NO_(3)+14e^-+28H^+

Reduction half reaction:
2ClO_4^(-)+14e^-+16H^+\rightarrow Cl_2+8H_2O

Hence, total 14 electrons are transferred.

User AlexGad
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