Question

12. How does the temperature of .033 kg of graphite change when it absorbs 350 J of thermal energy? (Graphite = 710 J/kgC)

Answer 1

14.94°C

Step-by-step explanation:

Given parameters:

Mass of graphite = 0.33kg

Quantity of heat absorbed = 350J

Specific heat capacity of graphite = 710J/kg°C

Unknown:

Temperature change = ?

Solution:

To solve this problem, we use;

H = m c Ф

H is the quantity of heat

m is the mass

c is the specific heat capacity

Ф is the change in temperature

350 = 0.033 x 710 x Ф

Ф = 14.94°C