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(3x^2+3)+(3x^2+x+4)?

User Collector
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2 Answers

5 votes

Answer:

6x^2+x+7

Explanation:

(3x^2+3)+(3x^2+x+4)

6x^2+3+x+4

6x^2+x+7

User M Swapnil
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5.8k points
3 votes

You first start with adding the number in the parentheses,because none of them can add in this equation it stays the same:

(3x^2 + 3) + (3x ^2 + x + 4)

Since there is nothing that we can do while there are parenthaseese we remove them:

3x^2 + 3 + 3x ^2 + x + 4

Next add the x^2’s:

6x^2 + 3 + x + 4

Lastly the normal numbers:

6x^2 + 7 + x

Now that there are no more numbers that are the same, 6x^2 + x + 7 is your simplified equasion.

Hope this helps! :)

User Peter Theill
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5.7k points