Question

ASAP PLZ!!!!! Select the correct answer. What are the solutions of this quadratic equation? 2x2 + 16x − 8 = 0 A B. C. D.

Answer 1

`x=-4+2√(5)`

`x=-4-2√(5)`

Explanation:

The formula to solve a quadratic equation of the form

`ax^(2) +bx+c=0`

is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`2x^(2) +16x-8=0`

so

`a=2\\b=16\\c=-8`

substitute in the formula

`x=\frac{-16(+/-)\sqrt{16^(2)-4(2)(-8)}} {2(2)}`

`x=\frac{-16(+/-)√(320)} {4}`

`x=\frac{-16(+/-)8√(5)} {4}`

`x=-4(+/-)2√(5)`

therefore

The solutions are

`x=-4+2√(5)`

`x=-4-2√(5)`