Answer:
The mid point of segment connecting (-1, -9) and (-10, 4) is
![((-11)/(2) , (-5)/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w2bp5anblpoker2vm06kz3f3qam5w03n3o.png)
Explanation:
The coordinates of the given points are A(-1,-9) and B (-10,4).
Here, let us assume the point P (x,y) is the mid point of the segment AB.
By MID POINT FORMULA:
The mid point of segments with points ( x1,y1) and (x2,y2) is given as:
![(x,y) = ((x_1 +x_2)/(2) , (y_1 +y_2)/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zfk5vdj1hco79l1v80f08ssxmrlcfuy1gy.png)
So, here the coordinates of P are :
![(x,y) = ((-1 + (-10))/(2) , (-9+ 4)/(2)) = ((-11)/(2) , (-5)/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rdh7xlzvnyzk2n0gaw1y4rjfp0cz3gf26p.png)
⇒
![P(x,y) = ((-11)/(2) , (-5)/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x0x4pjp5fndsfhxnk4otwwetzlqew8jbrm.png)
Hence, the mid point of segment connecting (-1, -9) and (-10, 4) is
![((-11)/(2) , (-5)/(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w2bp5anblpoker2vm06kz3f3qam5w03n3o.png)