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A 0.74 mF capacitor is connected to a standard outlet (rms voltage 82 V, frequency 49 Hz ). Determine the magnitude of the current in the capacitor at t

User VonGohren
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1 Answer

3 votes

Answer:

I = 26.36 cosω t A

Step-by-step explanation:

Given that

C=0.74 mF

Vrms= 82 V

Frequency ,f= 49 Hz

We know that ω = 2 π f

ω = 2 x π x 49

ω = 307.72 rad/s

As we know that voltage given as

V= Vo sinω t


V_o=\sqrt2\ V_(rms)


V_o=\sqrt2\ * 82\

Vo=115.96 V

V=115.96 sinω t

The current given as


I=C(dV)/(dt)


I=0.74* (dV)/(dt)\ mA


(dV)/(dt)=115.96\omega cos\omega t


I=0.74* 115.96* 307.22 cos\omega t\ mA

I = 26362.67 cosω t mA

I = 26.36 cosω t A

This is the current at time ant time t.

User Checksum
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