Answer:
6² + 11² = c²
Explanation:
If we consider a right triangle Δ ABC, whose side AB and side BC are the two perpendicular legs, then AC is considered to be the hypotenuse.
Now, if the length of one leg AB is to be 6 units and the length of the other leg BC is to be 11 units.
Then the length of the hypotenuse, c is given by
AC² = AB² + BC² {Applying Pythagoras Theorem}
⇒ c² = 6² + 11²
⇒ 6² + 11² = c² (Answer)