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The product of the nuclear reaction in which 40Ar is subjected to neutron capture followed by alpha emission is ________. The product of the nuclear reaction in which 40Ar is subjected to neutron capture followed by alpha emission is ________. 37S 35Ar 36S 45Ca 41Ar

User DownChapel
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Answer: 37S

Step-by-step explanation:

Radioactivity is the spontaneous emission of particles and / or electromagnetic radiation by unstable atomic nuclei leading to their disintegration.

We have two main types of radioactivity: radioactive decay and artificial transmutation.

In radioactive decay ( natural radioactivity ), a naturally occurring radioactive element like Uranium-238 disintegrates or decays into more stable isotopes with the emission of particles and/or radiation.

[Tex]23892U = 23490Th + 42He[/Tex]

Artificial transmutation is the collision of two particles where one particle captures the other used to bombard it. There is subsequent production of isotopes similar or different from the bombarded particle. Neutrons, alpha particles ( helium nucleus ), electrons, protons can be used to bombard elements.

[Tex]147N + 42He = 178O + 11P[/Tex]

For the above question which is artificial transmutation, the reaction equation is

[Tex]4018Ar + 10n = 3716S + 42He[/Tex]

So, the neutron capture by Argon-40 will produce a radioisotope Sulphur-37 with the emission of an alpha particle.

To check if your answer is correct total mass number must be equal on both equation sides 40+1 = 41; 37+4= 41. And total atomic number must be equal on both equation sides 18+0= 18; 16+2=18.

User Mithun Sasidharan
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