Answer:
W = 49000 J
Step-by-step explanation:
Given that,
Length of the cable, l = 50 m
Density of the cable,
![d=4\ kg/m](https://img.qammunity.org/2020/formulas/physics/college/yl09qldld1hhm3zhudqm83grpxq0tecjxj.png)
The force acting on the cable is variable and it is equal to,
![F=4l\ g](https://img.qammunity.org/2020/formulas/physics/college/7on8ex02666vonh1tce7mkfzygoreremv1.png)
Let W is the work is needed to pull the whole cable to the top of the building. It is given by :
![W=\int\limits^(50)_0 {4lg\ dl}](https://img.qammunity.org/2020/formulas/physics/college/wzxsil2nh1gh1k4oq9rjvimdtzsa6da6go.png)
![W=39.2\int\limits^(50)_0 {l.dl}](https://img.qammunity.org/2020/formulas/physics/college/vpqymmw4qrybj0q4ma9b23ykhrxduz2tdr.png)
![W=(39.2l^2)/(2)|_0^(50)](https://img.qammunity.org/2020/formulas/physics/college/6xe432jjspgosh338pa35d43hdca6qkviw.png)
W = 49000 J
So, the work needed to pull the whole cable to the top of the building is 49000 J. Hence, this is the required solution.