Question

A 0.145- kg baseball with an initial speed of 29 m/s rebounds with a speed of 36 m/s after being struck with a bat. If the duration of contact between ball and bat was 1.8 ms, what was the magnitude of the average force between ball and bat?

Answer 1

The average force between ball and bat, F = 5236.11 N

Step-by-step explanation:

Given that,

Mass of the baseball, m = 0.145 kg

Initial speed of the baseball, u = 29 m/s

Final speed of the ball, v = -36 m/s (negative as it rebounds)

Time,
`t=1.8\ ms=1.8* 10^(-3)\ s`

Let J is the impulse imparted by the ball. It is equal to the change in momentum as :

`J=m(v-u)=Ft`

`F=(m(v-u))/(t)`

`F=(0.145* (-36-29))/(1.8* 10^(-3))`

F = -5236.11 N

|F| = 5236.11 N

So, the magnitude of the average force between ball and bat is 5236.11 N. Hence, this is the required solution.