Question

The specific heat of a certain type of cooking oil is 1.75 J / ( g ⋅ ° C ) . 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of 2.87 kg 2.87 kg of this oil from 23 ° C 23 °C to 191 ° C?

Answer 1

Q =843780 J

Step-by-step explanation:

Given that,

The specific heat of a certain type of cooking oil is,
`c=1.75\ J/g^(\circ)C`

Mass of the oil, m = 2.87 kg = 2870 g

Initial temperature,
`T_i=23^(\circ)C`

Final temperature,
`T_f=191^(\circ)C`

To find,

Heat energy needed to raise the temperature.

Solution,

The heat energy needed to raise the temperature in terms of specific heat is given by :

`Q=mc(T_f-T_i)`

`Q=2870\ g* 1.75\ J/g^(\circ)C* (191^(\circ)C-23^(\circ)C)`

`Q=843780\ J`

So, the heat energy needed to raise the temperature is 843780 J.