Question

A sample of neon gas at a pressure of 0.571 atm and a temperature of 219 °C, occupies a volume of 604 mL. If the gas is heated at constant pressure until its volume is 838 mL, the temperature of the gas sample will be ______ °C.

Answer 1

409.67 °C

Step-by-step explanation:

At constant pressure and temperature, using Charle's law as:-

`\frac {V_1}{T_1}=\frac {V_2}{T_2}`

Given ,

V₁ = 604 mL

V₂ = 838 mL

T₁ = 219 °C

T₂ = ?

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (219 + 273.15) K = 492.15 K

Using above equation as:

`(604\ mL)/(492.15\ K)=(838\ mL)/(T_2)`

`T_2=(838* 492.15)/(604)\ K=682.82\ K`

In Celsius, the temperature is:- 682.82-273.15 °C = 409.67 °C