Question

Combining 0.247 mol Fe 2 O 3 0.247 mol Fe2O3 with excess carbon produced 14.0 g Fe . 14.0 g Fe. Fe 2 O 3 + 3 C ⟶ 2 Fe + 3 CO Fe2O3+3C⟶2Fe+3CO What is the actual yield of iron in moles?

Answer 1

Answer : The actual yield of iron in moles is 0.25 moles.

Solution : Given,

Mass of Fe = 14.0 g

Molar mass of Fe = 56 g/mole

Now we have to calculate the moles of
`Fe`.

Formula used :

`\text{ Moles of }Fe=\frac{\text{ Mass of }Fe}{\text{ Molar mass of }Fe}`

Now put all the given values in this expression, we get:

`\text{ Moles of }Fe=(14.0g)/(56g/mole)=0.25moles`

Therefore, the actual yield of iron in moles is 0.25 moles.