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Within a population of moths, the color black (B) is dominant over the color gray (b). 40% of moths in a given population in an urban park are black. Over time, the tree bark darkens and the black moths become camouflaged. Eventually only 4% show the recessive phenotype, gray. What are the frequencies of the p and q alleles in the final population? A) p = .4; q = .6 B) p = .8; q = .2 C) p = .96; q = .04 D) p = 9.6; q = .4

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Answer:

B) p=,8; q=.2

Step-by-step explanation:

I found out using the process of elimination on the quiz till I got a 100%.

User Firas Omrane
by
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1 vote

Answer:

C

Explanation: consider the genotype frequency . p²+q²+2pq=1

where the total is always 100% also represented as 1.

First the Black moths are which are dominant, and in our above equation at 40 %The dominant homozygous is represented by p which = .40

But eventually q the recessive homozygous is 4% which is = .04

with this information we then find the final percentage of P

which is p=1.00-.04=.96

p=.96 since q= .04 in the final population.

User Bgroenks
by
7.6k points

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