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What is the cost for the problem below

What is the cost for the problem below-example-1
User Jestges
by
7.3k points

2 Answers

6 votes

Answer:

770

Explanation:

because if u add 450+320 equal 770 so that your answer

User Sirthomas
by
7.7k points
1 vote

Answer: it will cost $3190.752

Explanation:

Step 1

We would determine the length of the side of the field, AC. To do this, we would apply the cosine rule. Since we know sides AB and BC and angle B, It will be expressed as

b^2 = a^2 + c^2 - 2acCosB. It becomes

b^2 = 320^2 + 450^2 - 2×320×450Cos80

= 102400 + 202500 - 144000Cos80

= 304900 - 24998.4

b^2 = 279901.6

b= √279901.6

b = 529.06 yards

Step 2

We would determine the area of the triangle. The formula for the area of the triangle is expressed as

Area of triangle = 1/2 × acSinB

Area of triangle = 1/2 × 320 × 450 × Sin 80

Area of triangle = 72000 × 0.9848 = 70905.6 yards^2

If 100 square yards cost $4.50

70905.6 square yards cost (70905.6×4.5) /100 = $3190.752

User Infotekka
by
7.6k points