Question

Find the mass in grams of 3.00 x 1023 molecules of F2

Answer 1

18.9 g F₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

3.00 × 10²³ molecules F₂

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

Step 3: Convert

1. Set up:
   `\displaystyle 3.00 \cdot 10^(23) \ molecules \ F_2((1 \ mol \ F_2)/(6.022 \cdot 10^(23) \ molecules \ F_2))((38.00 \ g \ F_2)/(1 \ mol F_2))`
2. Multiply:
   `\displaystyle 18.9306 \ g \ F_2`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

18.9306 g F₂ ≈ 18.9 g F₂