Answer:
public boolean oddsMatchEvens(int[ ] w, int[ ] q) {
for (int i = 0; i < w.length-1; i+=2) {
if (w[i] != q[i + 1])
return false;
else
continue;
}
return true;
}
Step-by-step explanation:
Since it was mentioned that both arrays are of equal length, we use the length of the first array minus one as our condition in order check the last item. Then, we have to check first array even with second array odd so we increment by be i+=2 and not the popular i++. The continue statement ensures that as soon as only one case fails, the loop with stop and return true.