Question

You need to prepare 250. mL of a 0.300 M aqueous solution of sucrose, C12H22O11 (aq), which is used frequently in biological experiments.Based on your answer above, what is the value of x?

Answer 1

The question is incomplete, here is the complete question:

You need to prepare 250. mL of a 0.300 M aqueous solution of sucrose,
`C_(12)H_(22)O_(11)` (aq), which is used frequently in biological experiments. Based on your answer above, measure out the amount of solid sucrose in the solution.

Answer: The mass of solid sucrose present in the solution is 25.7 grams.

Step-by-step explanation:

To calculate the mass of sucrose, we use the equation used to calculate the molarity of solution:

`\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}`

Molarity of solution = 0.300 M

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 250. mL

Putting values in above equation, we get:

`0.300mol/L=\frac{\text{Mass of sucrose}* 1000}{342.3g/mol* 250.}\\\\\text{Mass of sucrose}=(0.300* 342.3* 250.)/(1000)=25.7g`

Hence, the mass of solid sucrose present in the solution is 25.7 grams.