Answer:
Q = -150.8 J
Step-by-step explanation:
Given data:
Mass of copper = 10.0 g
Initial temperature = 80.0°C
Heat released = ?
Final temperature = 40.0 °C
Specific heat capacity of copper = 0.377J/(g·ºC)
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 40.0 °C - 80.0 °C
ΔT = -40.0 °C
by putting values,
Q = 10.0 g × 0.377J/g·ºC× -40.0 °C
Q = -150.8 J