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to the nearest tenth, find the perimeter of triangle ABC with vertices A (3, 2), B (-2,3), and C (2,6)​
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5 votes
to the nearest tenth, find the perimeter of triangle ABC with vertices A (3, 2), B (-2,3), and C (2,6)​

User Niken
by
9.1k points

2 Answers

2 votes

Answer:

15

to nearest tenth 20

Explanation:

AC = 4 cm

AB = 5 cm

BC = 6 cm

4+5+6=15 to nearest tenth 20

User Ftkg
by
8.4k points
1 vote

Answer:

14.2

Explanation:

User Arin
by
8.3k points
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