Question

Identify the limiting reactant when 1.78 gram of oxygen reacts with 2.16 grams of hydrogen to produce water.

Answer 1

oxygen is limiting reactant.

Step-by-step explanation:

Given data:

Mass of oxygen = 1.78 g

Mas of hydrogen = 2.16 g

Limiting reactant = ?

Solution:

Chemical equation:

2H₂ + O₂ → 2H₂O

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 1.78 g / 32 g/mol

Number of moles = 0.06 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 2.16 g / 2 g/mol

Number of moles = 1.08 mol

No we will compare the moles of oxygen and hydrogen with water.

O₂ : H₂O

1 : 2

0.06 : 2×0.06 = 0.12 mol

H₂ : H₂O

2 : 2

1.08 : 1.08

Number of moles of water produced by oxygen are less so oxygen will be limiting reactant.