Answer:
For the average to be above 90, the marks in the fourth paper should be MORE THAN 92.
Explanation:
The score of students in last 3 exams = 89 , 87 and 92
Let us assume the marks scored by the student in last exam = k
The average of marks should be above 90.
Now,
![\textrm{The average of total marks} = \frac{\textrm{Sum of all marks obtained in 4 papers}}{\textrm{ 4 papers }}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/omneu5179145uog96xn9h0zdplcqmggd69.png)
Sum of all 4 paper's marks = 89 + 87 + 92 + k = 268 + k
Also, 90 < Average
![\implies 90 < (268 + k)/(4)\\ or, 360 < 268 + k\\\implies 360 - 268 < k\\or, k > 92](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nwtryziqndqm092sdk1daf0y80zyw5kl3u.png)
Hence,for the average to be above 90, the marks in the fourth paper should be MORE THAN 92.