Question

You spend $27 on seven bags of candy to throw while you participate in a parade.

The bags cost either $5 or $3. How many bags of each amount did you purchase?

Answer 1

To find the number of $5 and $3 bags of candy purchased for a total of $27, set up two equations and solve the system. You would have bought 3 bags at $5 each and 4 bags at $3 each.

Step-by-step explanation:

You are trying to determine how many bags of candy you purchased at $5 and $3 given that you spent a total of $27 on seven bags. We can start by setting up two equations to represent the situation:

• Let the number of $5 bags be x.

• Let the number of $3 bags be y.

The first equation represents the total number of bags:

• x + y = 7

The second equation represents the total amount spent:

• 5x + 3y = 27

Now let's solve this system of equations:

• From the first equation, solve for y: y = 7 - x.

• Substitute y = 7 - x into the second equation: 5x + 3(7 - x) = 27.

• Simplify the equation: 5x + 21 - 3x = 27.

• Combine like terms: 2x = 6.

• Divide both sides by 2 to get: x = 3.

• Now, substitute x back into y = 7 - x to get y: y = 7 - 3 = 4.

Therefore, you purchased 3 bags at $5 each and 4 bags at $3 each.

Answer 2

You bought 3 bags of the $5 candy. and 4 bags of the $3.
3*$5= $15
4*$3= $12
$15+$12= $27