Answer:
Probability of drawing a 7 or an 8 is
![(2)/(13)](https://img.qammunity.org/2020/formulas/business/college/ujr0p5q0ln64uoif1ofl08hp8j6fo0qjnh.png)
Explanation:
Total number of cards in the given deck = 52
Now, the number of 7 in the deck = 4
Also, the number of 8 in the deck = 4
So, the total number of ( 7 + 8) in the deck = 4 + 4 = 8 cards
Let E: Event of picking a 7 or an 8
Here, the total number of favorable outcomes = 8
Now,
![\textrm{P(E) } = \frac{\textrm{Number of outcomes favorable to E }}{\textrm{Total number of outcomes}}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8sfmf9oiwbw0jxw2guemwbaa9u0x9eyey6.png)
So, here
![\textrm{P(Picking a 7 or 8) } = \frac{\textrm{8 }}{\textrm{52}} = (2)/(13)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sn0pquribua3j7vmx4bqkfu9olutjh9wol.png)
or, P(Picking a 7 or 8) = 2/13
Hence, The probability of drawing a 7 or an 8 is
![(2)/(13)](https://img.qammunity.org/2020/formulas/business/college/ujr0p5q0ln64uoif1ofl08hp8j6fo0qjnh.png)