Question

For the experiment of rolling an ordinary pair of dice, find the probability that the sum will be less than 3 or greater than 10.

Answer 1

Answer: 1/9

Explanation:

the total number of combinations or outcomes when 2 dice are rolled is 36 ( count all or simply the formula for total number of combinations or outcomes when n dice are rolled is
`6^(n)` )

sum possibilities probability(favorable/ total outcomes of the event)

2 (1,1) 1/36

3 (1,2) , (2,1) 2/36

4 (2,2), (3,1) , (1,3) 3/36

5 (4,1), (1,4),(2,3),(3,2) 4/36

6 (1,5),(5,1),(2,4),(4,2),(3,3) 5/36

7 (2,5),(5,2)(1,6),(6,1),(3,4),(4,3) 6/36

8 (2,6),(6,2), (5,3),(3,5),(4,4) 5/36

9 (3,6),(6,3),(5,4),(4,5) 4/36

10 (5,5),(4,6),(6,4) 3/36

11 (6,5),(5,6) 2/36

12 (6,6) 1/36

probability that the sum will be less than 3 or greater than 10 = probability for sum to be 2 + probability for sum to be 11 + probability for sum to be 12

= 1/36 + 2/36 + 1/36

= 4/36

= 1/9