Answer:
$595
e) If the company insures a large number of these cars, they can expect the average cost per car to be approximately E(C).
Explanation:
Given the distribution :
C $0 $500 $1000 $2,000
P(C) 0.60 0.05 0.13 0.22
Expected probability : E(C)
Σ[C * P(C)] = (0*0.60) + (500*0.05) + (1000*0.13) + (2000*0.22) = $595
Since the expected value could be interpreted as the average value of a random variable over a large Number of experiment or trials