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An object is placed near a concave mirror having a radius of curvature of magnitude 60 cm. How far should you place the object from the mirror so that the lateral magnification produced by the mirror will be 2.5?

User Squv
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1 Answer

4 votes

Answer:

u = 18 cm

Step-by-step explanation:

given,

radius of curvature = 60 cm

magnification of mirror = 2.5

distance of object = ?

R = 2 f

f = R/2

f = 60/2 = 30 cm


m = -(v)/(u)


2.5 = -(v)/(u)

v = -2.5 u

now,

Using mirror formula


(1)/(f) = (1)/(v) + (1)/(u)


(1)/(30) = (1)/(-2.5u) + (1)/(u)


(1)/(30) = (0.6)/(u)

u = 0.6 x 30

u = 18 cm

distance of object be equal to u = 18 cm

User Leontalbot
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