75.0k views
0 votes
A hot-air balloon consists of a basket hanging beneath a large envelope filled with hot air. A typical hot-air balloon has a total mass of 539 kg, including passengers in its basket, and holds 2.62 ✕ 103 m3 of hot air in its envelope. If the ambient air density is 1.27 kg/m3, determine the density (in kg/m3) of hot air inside the envelope when the balloon is neutrally buoyant. Neglect the volume of air displaced by the basket and passengers. HINT kg/m3

User Vargonian
by
4.6k points

1 Answer

5 votes

Answer:

1.05045 kg/m³

Step-by-step explanation:


\rho_a = Density of air = 1.26 kg/m³


\rho_(ha) = Density of hot air


m_a = Mass of balloon = 539 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Volume of air in balloon =
2.62* 10^3\ m^3

The net force on the balloon will be


F_n=(\rho_a-\rho_(ha))vg

Also


F_n=m_ag


\\\Rightarrow 549g=(\rho_a-\rho_(ha))vg\\\Rightarrow 549=(1.26-\rho_(ha))2.62* 10^3\\\Rightarrow -\rho_(ha)=(549)/(2.62* 10^3)-1.26\\\Rightarrow \rho_(ha)=1.05045\ kg/m^3

The density of hot air inside the envelope is 1.05045 kg/m³

User Dominic Cronin
by
4.5k points