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If csc theta = 8/7, which equation represents (cot theta) ?

A. Cot theta=√15/8
B. cot theta=√15 / 7
C. cot theta=7√15 / 15
D. cot theta= 8√15 / 15

2 Answers

6 votes

Answer:

Option B

Explanation:

just i took the test

User Sami Hult
by
6.0k points
3 votes

Out of the given choice, the equation represents
\cot \theta=(√(15))/(7).

Answer: Option B

Explanation:

We know,
\csc \theta=(1)/(\sin \theta)


\sin \theta=(1)/(\csc \theta)

Given data:


\csc \theta=(8)/(7)

So, now sin theta can express as


\sin \theta=\frac{7(\text { opposite })}{8(\text { Hypotenuse })}

Sin theta defined by the ratio of opposite to the hypotenuse. In general, the adjacent can be calculated by,


\text {(opposite) }^(2)+(\text { adjacent })^(2)=(\text {Hypotenuse})^(2)


7^(2)+(\text { adjacent })^(2)=8^(2)


(\text {adjacent})^(2)=8^(2)-7^(2)=64-49=15

Taking square root, we get


\text { adjacent }=√(15)

Also, we know the formula for cot theta,


\cot \theta=(1)/(\tan \theta)=(1)/(\left((\sin \theta)/(\cos \theta)\right))=(\cos \theta)/(\sin \theta)

Cos theta denoted as the ratio of adjacent to the hypotenuse.


\cos \theta=\frac{√(15)(\text {Adjacent})}{8(\text {Hypotenuse})}

Therefore, find now as below,


\cot \theta=(\left((√(15))/(8)\right))/(\left((7)/(8)\right))=(√(15))/(8) * (8)/(7)=(√(15))/(7)

User Umesh
by
5.3k points