Question

Balance the equation and determine how many liter of nitrogen are required to react with 7.3 L of hydrogen to produce ammonia (nitrogen trihydride)?

Answer 1

4.867 L of ammonia

Step-by-step explanation:

Using Haber's process to form ammonia using Nitrogen and hydrogen, the equation is :

N₂ + 3H₂ → 2NH₃

Here, 3 moles of hydrogen gas gives 2 moles of ammonia.

1 mole of any substance occupies 22.4L at STP

So, 3 x 22.4L of hydrogen gives 2 x 22.4 L of ammonia

Then 7.3 L of hydrogen will give:

=
`(7.3 * 2 *22.4 )/(3 *22.4)`

=
`(7.3 * 2)/(3)`

= 4.867 L of ammonia